SQL SERVER - OBTENIR LA POSITION DU PREMIER CHIFFRE D'UNE CHAINE DE CHARACTERES

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
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CREATE FUNCTION [dbo].[FN_CHARINDEX_FIRST_NUMERIC] (@NOMDIV nvarchar(30))
RETURNS smallint

AS

BEGIN

	DECLARE @nom nvarchar(30)
	DECLARE @i smallint
	DECLARE @j smallint
	SET @i = 1
	SET @j = 0

	WHILE @i < len(@nomdiv)
	BEGIN
		DECLARE @car nvarchar(1)
		SET @car = (SUBSTRING(@NOMDIV, @i, @i) )
		IF @car IN ('1', '2', '3', '4', '5', '6', '7', '8', '9', '0')
		BEGIN
			SET @j = @i
			BREAK
		END
		ELSE 
			SET @i = @i + 1
	END

RETURN @j
END
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-- Une seconde solution fournie par Christian plus performante

CREATE FUNCTION [dbo].[FN_CHARINDEX_FIRST_NUMERIC_V2] (@NOMDIV nvarchar(30))
RETURNS smallint

AS

BEGIN

  RETURN PATINDEX ('%[0123456789]%', @NOMDIV)

END